THE TIME NEEDED TO SET UP A GRADIENT: DETAILED CALCULATIONS By MARY MUNRO anpF. H.C. CRICK Medical Research Council Laboratory of Molecular Biology, Hills Road, Cambridge CB22QH, England INTRODUCTION In embryological development there ate many cells which acquire ‘posi- tional information’ (see, for example, Wolpert, 1969) and it is plausible that this is obtained from the concentration of certain unknowti chemicals (called here morphogens) which are diffusing down concentration gradients set up by sources and sinks at special places in the embryo. It is thetefore important to be able to calculate how much time is needed to set tip 4 steady concentration gradient. This problem has been discussed in a recent paper (Crick, 1970) which suggests that the times available are roughly what might be expected on theoretical grounds. Here we give the details of various’ calculations quoted in that paper. The physics and mathematics of diffusion are fairly straight-forward. The classic references are two books: The Conduction of Heat in Solids, by Carslaw and Jaeger, 2nd edition, 1959 (here referred to as C. and J.) and The Mathematics of Diffusion, by J. Crank, 1956. Results which could not be obtained easily in an algebraical form were calculated by computer. Although a tissue consists of discrete cells, we have often found it conven- ient to treat it as a continuous medium, in which the morphogen has a diffu- sion constant D cm?/s. On the other hand, in calculations on the computer, this continuous medium has usually been approximated by a series of dis- crete points. Details of these computations will be given later. For reasons explained in the earlier paper (Crick, 1970) it is reasonable to calculate one-dimensional cases, at least in the first instance. A SIMPLE LINEAR GRADIENT Mathematically, the simplest model to consider is one having a source at the origin, holding the concentration there to the value C,, and a sink at the point x = L, holding the concentration there to zero. If the diffusion con- stant, D, is everywhere the same, then after an infinite time the concentra- tion will tend to the value Cac! - —x LS [ 439 J (o> x > L). (1) 440 MARY MUNRO AND F. H. C. CRICK (Note that this expression does not contain D. However, the flux per unit area does depend on D, and is given by (DC,/L).) The concentration will approach this final value asymptotically. To calculate the amount by which the concentration at any time differs from its final value we adapt the formula given in C. and J. P- 99, section 3-4, equa- tion (1). The general value c for the concentration at the point x at time t is given by E-x_2Cy © =sin ("F* exp (—ntat) where c=f(x) at t=0, and thereafter c=Cy at x=0, c=o at x=L, We have expressed time in a convenient dimensionless form by putting T = (Dt/L?). In the first instance let us assume that the initial concentration is every- where zero (i.e. f(x) = 0). Then at any given time the maximum value of AC, the difference between the concentration and its final value, is at the midpoint « = }L, because of the symmetry of the problem. For this special case the value of AC is given by AC = — 70'S Lsin™ exp (—ntat), (3) If we only consider cases in which AC is small, we need take no more than the first two terms, so that 2Cy , AC = —~* [exp (—7T')—Jexp(—97°7)...] (4) and usually the first term alone will suffice. In Fig. 1 we plot the value of |AC/C,| against T (for the middle point). For example, if |AC/C,| is taken as 1%, then T has the value of 0-42. We have also computed the whole course of the concentration curve for certain selected values of 7, using equation (2). Linear gradient with initial constant background A smaller value of 7 (for a chosen value of AC/C)) can be obtained if we allow the tissue to have a uniform concentration of the morphogen at time THE TIME NEEDED TO SET UP A GRADIENT 441 zero. Let this be aC,. To be of any advantage « must be less than unity, In this case equation (2) becomes ~4E 2 3 Ur—cosnm)—1 (“) exp(—n'nT), (5) Cy math n It is only necessary to take the first two terms of this series, since for the particular times we are interested in, the third and higher terms are neglig- ible (for T= 0-1, n = 3, exp(—n°7°T) = 2x 10-7). For the special case 0-00 ! ! l t ! 0-20 0-25 0-30 0-35 0-40 0-45 0-50 0-55 0-60 0-65 0-70 Time T Fig. 1. AC/C, for the mid-point of the gradient as it approaches its final value. a=} the term having 2 = 1 is zero, and the maximum value of |AC} occurs at the points x/L = } or }. It turns out that for values of a less than unity but not too close to a = } (that is, when a is between o and O-4, or 0-6 and 3-0) we can neglect all but the first term. For |AC/C,| = o-o1 we easily derive the explicit equations: x I 200 at T= T = slog. aan), x at >=]. 1 100 L T= 73 !0Be “7 N2 (20 — 1) or =} where T is, in this case, the time at which |AC/C,| is 1% at the point under consideration. By symmetry, T for x/L = t with initial background aC, will be the same as T for x/L = } with initial background (1 —@) Cy. The values thus obtained are set out in Table 1. 442 MARY MUNRO AND F. H. C. CRICK 0-35 Tt O24 aoc “me 0-1 } | 1 | ! J 1 I I 00 Of 02 03 04 O05 06 07 O8 OF 10 a 0-0 Fig. 2. Time taken for the concentration at all points to come within 1% of their final values, for different initial backgrounds (a@C,). Table x Values of T for |AC/C,| equal to o-o1 for the point specified, for various values of the initial background @C,, calculated using only a single (non-zero) term in the expansion. The value in brackets is inaccurate. At At x/L = } (foro < @ < a5) a x/L = 4 or x/L = } (for o-5 < a@ < 1-0) a 0°05 O°410 0375 0°95 o'10 0°398 0°363 9°90 O15 0385 0°350 085 0:20 0°369 0°334 o'80 O25 O°351 O°315 o-75 0"30 0°328 0'293 0'70 0°35 0°299 0264 0°65 "40 0258 0'223 0-60 o-45 0188 (0-15) Oss 0°50 90°000 0088 0°50 THE TIME NEEDED TO SET UP A GRADIENT 443 For values of « outside the limits 0-45 to o- 55 the last point to fall within the 1% limit is always the mid-point. However, this is not true when a = 4, since AC at the mid-point is at all times zero (because of the sym- metry), and the last point to fall within the 1 % limit is x/L = } or x/L = 3. For values of a in between 0-45 and o-5 the last point will be somewhere between x/L = } and x/L = 4, and can be roughly estimated. For example, when a = 0-475 the last point is approximately x/Z = 0:35, when T ~ 0°126. We then adopt as a criterion the condition that all points on the gradient must be within 1% of the final concentration difference between the ends of the gradient from their final values, and define 7” as the time taken fot this to occur. Fig. 2 shows the approximate value of 7” for all values of a between oand 1. The values near @ = }, shown dotted in the curve, have been roughly estimated from computer calculations for a = 0-45 and & = 0-475, It will be seen that although a rather small value of 7” can be obtained if a is exactly 4, the value of 7” rapidly increases if « differs appreciably from this special value. However, if the level of a were within + 10% of this special value, 7’ would always be less than o-I9. Other initial conditions We have shown that if there is zero concentration initially, the time taken to set up an almost linear gradient is longer than for any other initial UNIFORM concentration less than C,. By symmetry this time is the same as the time when the initial concentration is Cy throughout. We now prove that if the initial concentration has any arbitrary form, but is always less than C, (and always positive), it takes a shorter time to set up a nearly linear gradient than the simple case with zero initial background. The time taken to set up the simple case is approximately T = 0-4. When T = 0-4, exp(—7°T) = 0-0193 and exp (—47°T) = 1-7 x 1077. Looking at the concentration equation (2), the second term is co ae “sin (") exp (—n*7?T). Whenn = 2and T ~ o-4 thisis always numerically less than (1-7 x 10-7) C,/7 and is clearly negligible. Whenz > 3 and T' ~ 0-4 the terms are very much smaller. Looking at the third term of the equation (2), since 0 < f(x) < Cy by definition and ~—I 2 when T is as great as 0-4. So the concentration function ignoring 1 > 2 is c= aes —2sin ey) exp(—7°T) [= _ i | . J(«')sin (*) a:'| AC = asin (=) exp(—7°T) [s -; I . ‘A (sin 7) as'| . 6 When f(x) = 0, initially we get thus JAC| = 2 sin (=) exp(—7°T), as before, but 0 < f(x) < Cy . (1x . and o $, arid f(x) is always positive, the function which would give the largest possible value to this term is the step function: . f(x)=0 for o J(x)=Cy for 4 This integrates to give